z^2+(2i-3)+(5-i)=0

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Solution for z^2+(2i-3)+(5-i)=0 equation:


Simplifying
z2 + (2i + -3) + (5 + -1i) = 0

Reorder the terms:
z2 + (-3 + 2i) + (5 + -1i) = 0

Remove parenthesis around (-3 + 2i)
z2 + -3 + 2i + (5 + -1i) = 0

Remove parenthesis around (5 + -1i)
z2 + -3 + 2i + 5 + -1i = 0

Reorder the terms:
-3 + 5 + 2i + -1i + z2 = 0

Combine like terms: -3 + 5 = 2
2 + 2i + -1i + z2 = 0

Combine like terms: 2i + -1i = 1i
2 + 1i + z2 = 0

Solving
2 + 1i + z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + 1i + -2 + z2 = 0 + -2

Reorder the terms:
2 + -2 + 1i + z2 = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 1i + z2 = 0 + -2
1i + z2 = 0 + -2

Combine like terms: 0 + -2 = -2
1i + z2 = -2

Add '-1z2' to each side of the equation.
1i + z2 + -1z2 = -2 + -1z2

Combine like terms: z2 + -1z2 = 0
1i + 0 = -2 + -1z2
1i = -2 + -1z2

Divide each side by '1'.
i = -2 + -1z2

Simplifying
i = -2 + -1z2

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